2024 AS Practical S2
Study Notes:
Question 1: Osmosis and Plasmolysis
1(a) Experimental Design and Interpretation
1(a)(i) Identifying Variables and Observations
- Independent Variable:
- Solution Concentration of Sodium Chloride
- Clearly label this as the independent variable in your experiment.
- Solution Concentration of Sodium Chloride
- Dependent Variable:
- Number of Cells Showing Plasmolysis
- Clearly label this as the dependent variable.
- Number of Cells Showing Plasmolysis
- Key Observations:
- U1 (Highest Concentration): Most plasmolysis observed.
- U2 (Lowest Concentration): Least plasmolysis observed.
- Marks Allocation:
- Correctly identifying variables and observations: 4 Marks
1(a)(ii) Concentrations of Sodium Chloride Solutions
- Three Concentrations:
- 0.10 mol dm⁻³: U2
- 0.50 mol dm⁻³: U3
- 1.00 mol dm⁻³: U1
- Key Points:
- Ensure accurate identification and association of concentrations with their respective units.
- Marks Allocation:
- Correctly identifying concentrations and their labels: 1 Mark
1(a)(iii) Drawing Cells Showing Plasmolysis
- Drawing Requirements:
- Minimum Size and Clarity:
- All lines should be sharp and continuous.
- Number of Cells:
- Draw four whole cells, ensuring each cell touches at least two others.
- Cell Walls and Membranes:
- Draw the cell wall as two lines around each cell.
- Draw three lines where cells touch to represent the shared cell walls.
- Correct Cell Shape:
- Ensure cells are accurately shaped (typically circular or oval).
- Labeling:
- Label at least one cell surface membrane.
- Minimum Size and Clarity:
- Marks Allocation:
- Each correct element contributes to the total of 5 Marks.
1(a)(iv) Explaining Plasmolysis
- Key Explanation Points:
- Water Potential Gradient:
- Water potential is lower in solution U1 than in the onion cells.
- Water Movement:
- Water moves out of the cells from high to low water potential by osmosis.
- Plasmolysis Observation:
- The cell membrane pulls away from the cell wall.
- Water Potential Gradient:
- Alternative Explanation:
- If no plasmolysis is observed in part (a)(iii), explain accordingly.
- Marks Allocation:
- Correctly explaining the process: 3 Marks
1(b) Data Analysis and Graphing
1(b)(i) Calculating Percentage Change in Mass
- Formula Used: Percentage Change=(Final Mass−Initial MassInitial Mass)×100\text{Percentage Change} = \left(\frac{\text{Final Mass} – \text{Initial Mass}}{\text{Initial Mass}}\right) \times 100Percentage Change=(Initial MassFinal Mass−Initial Mass)×100
- Example Calculation:
- If Initial Mass (M) = 2.3 g
- Final Mass (F) = 2.4 g
- Percentage Change = 2.4−2.32.3×100=4.35%\frac{2.4 – 2.3}{2.3} \times 100 = 4.35\%2.32.4−2.3×100=4.35%
- Marks Allocation:
- Correct application of the formula: 1 Mark
1(b)(ii) Additional Calculations
- Procedure:
- Addition of values from (b)(i) and (b)(ii) and then dividing by 3.
- Marks Allocation:
- Correct calculation method: 1 Mark
1(b)(iii) Drawing and Labeling a Graph
- Graph Requirements:
- Axes Labels:
- X-axis: Sucrose concentration (mol dm⁻³)
- Y-axis: Mean percentage change in mass
- Scales:
- X-axis: 0.2 mol dm⁻³ to 2 mol dm⁻³, labeled at least every 2 units.
- Y-axis: 2% to 2 cm, labeled at least every 2 units.
- Data Plotting:
- Plot all five data points using small crosses or dots within circles.
- Line of Best Fit:
- Connect points with a thin, ruled line of best fit.
- Axes Labels:
- Marks Allocation:
- Proper labeling and scaling: 2 Marks
- Correct plotting and line of best fit: 4 Marks
1(b)(iv) Estimating Values from the Graph
- Key Points:
- Accurately estimate specific data points based on the graphed trend.
- Marks Allocation:
- Correct estimation: 1 Mark
Question 2: Plant Root Anatomy and Starch Concentration
2(a) Drawing and Labeling Root Sections
- Drawing Requirements:
- Utilization of Space:
- Use most of the available drawing area.
- Correct Section:
- Draw the correct section of the root without including individual cells.
- Number of Tissues:
- Correctly represent the number of different tissues present.
- Proportion of Vascular Tissue:
- Accurately depict the proportion of vascular tissue relative to the entire root section.
- Labeling:
- Include labels for key structures, specifically labeling the xylem tissue.
- Utilization of Space:
- Marks Allocation:
- Each correct element contributes to the total of 5 Marks.
2(b) Starch Concentration and Data Interpretation
2(b)(i) Setting Up Serial Dilutions
- Procedure:
- Concentrations Used:
- 0.1 mol dm⁻³, 0.01 mol dm⁻³, 0.001 mol dm⁻³, 0.0001 mol dm⁻³
- Transfer Process:
- Transfer 1 cm³ from the previous beaker to the next.
- Adding Water:
- Add 9 cm³ of water to each beaker.
- Concentrations Used:
- Marks Allocation:
- Correct concentrations and procedural steps: 7 Marks
2(b)(ii) Creating a Table of Starch Concentrations
- Table Requirements:
- Headings:
- Independent Variable: Percentage concentration of starch (no units in the table body)
- Dependent Variable: [Specify as per experiment]
- Symbols:
- Use symbols to represent concentrations.
- Ensure symbols for higher concentrations (R1) are more numerous than those for lower concentrations (R2).
- Marks Allocation:
- Correct headings and symbols: 3 Marks
- Headings:
2(b)(iii) Observing and Recording Color Changes
- Key Points:
- Use appropriate color indicators to represent starch presence.
- Marks Allocation:
- Correct use of color: 1 Mark
2(b)(iv) Recording Observations
- Key Points:
- Record that R1 shows a higher number of symbols (indicating more starch) than R2.
- Marks Allocation:
- Correct recording of observations: 1 Mark
2(b)(v) Estimating Starch Concentrations
- Key Points:
- Accurately estimate starch concentrations for R1 and R2 based on experimental results.
- Marks Allocation:
- Correct estimation: 1 Mark
2(b)(vi) Suggesting Improvements to the Experiment
- Suggestions:
- Repeat and Find the Mean:
- Increase reliability by averaging multiple trials.
- Use a Colorimeter:
- Enhance accuracy in measuring color changes quantitatively.
- Use More Concentrations with Narrower Intervals:
- Improve precision in determining the relationship between concentration and starch presence.
- Repeat and Find the Mean:
- Marks Allocation:
- Any two valid suggestions: 2 Marks
2(b)(vii) Interpreting Results
- Key Points:
- R2 has less starch present compared to R1.
- Marks Allocation:
- Correct interpretation: 1 Mark
2(c) Comparing Root Structures
- Differences to Highlight:
- Root Hairs:
- Figure 2.4: Absent
- Figure 2.5: Present
- Vascular Bundle Size:
- Figure 2.4: Smaller
- Figure 2.5: Larger
- Endodermis Thickness:
- Figure 2.4: Thinner
- Figure 2.5: Thicker
- Cortex Size:
- Figure 2.4: Larger
- Figure 2.5: Smaller
- Root Hairs:
- Marks Allocation:
- Highlighting three correct differences: 3 Marks
Question 3: Cardiovascular Structures and Gas Exchange
3(a) Comparing Arteries, Capillaries, and Veins
- Table Comparison:
Feature | Artery | Capillary | Vein |
---|---|---|---|
Smooth Muscle | ✓ | X | ✓ |
Endothelium | ✓ | ✓ | ✓ |
Tunica Media | ✓ | X | ✓ |
- Key Points:
- Arteries and Veins: Contain smooth muscle and tunica media.
- Capillaries: Lack smooth muscle and tunica media; composed solely of endothelium.
- Marks Allocation:
- Correctly completing the table: 3 Marks
3(b) Gas Exchange in Lungs
3(b)(i) Labeling Gas Movement Arrows
- Oxygen (O₂):
- Moves from the alveolar space into the capillary lumen.
- Carbon Dioxide (CO₂):
- Moves from the capillary lumen into the alveolar space.
- Marks Allocation:
- Correct labeling of gas movements: 1 Mark
3(b)(ii) Factors Enhancing Gas Exchange
- Key Factors:
- Deoxygenated Blood:
- Arrives in alveolar capillaries with low partial pressure of oxygen.
- Oxygen Uptake:
- Oxygen binds to hemoglobin, forming oxyhemoglobin.
- Continuous Removal of Oxygenated Blood:
- Transported away via pulmonary veins.
- Extensive Capillary Network:
- Increases surface area for gas exchange.
- Ventilation:
- Maintains a high concentration gradient between alveolar air and blood.
- Deoxygenated Blood:
- Alternative Points:
- Ventilation maintains a large concentration difference, enhancing diffusion.
- Marks Allocation:
- Any four correct factors: 4 Marks
3(c) Identifying Pulmonary Vein
- Characteristics:
- Type of Vein: Pulmonary vein is a semilunar vein.
- Other Semilunar Veins: Aortic and pulmonary.
- Function: Carries oxygenated blood from the lungs to the heart.
- Marks Allocation:
- Correct identification and labeling: 3 Marks
Question 4: Plant Physiology and Biochemical Processes
4(a) Suberin and Lignin in Plant Tissues
- Suberin:
- Function: Hydrophobic barrier found in the Casparian strip of endodermal cells.
- Properties:
- Impermeable to water, forcing water to move through the symplast.
- Controls the movement of solutes into the xylem.
- Prevents toxins and pathogens from entering the vascular system.
- Lignin:
- Function: Provides structural support in cell walls of xylem vessel elements.
- Properties:
- Hydrophobic and impermeable to water loss.
- Prevents collapse of xylem vessels under negative pressure during water transport.
- Adds rigidity and strength to plant tissues.
- Marks Allocation:
- Any four correct points covering suberin and lignin: 4 Marks
4(b) Enzyme Mechanism: Laccase Action on Monolignols
- Laccase Enzyme:
- Function: Catalyzes the oxidation of monolignols to form lignin.
- Mechanism:
- Induced Fit:
- Active site undergoes a shape change to bind monolignols.
- Enzyme-Substrate Complex:
- Monolignols bind to the active site, facilitating the reaction.
- Catalysis:
- Lowers the activation energy required for the oxidation of monolignols.
- Product Release:
- Laccase returns to its original shape after the reaction.
- Induced Fit:
- Additional Points:
- Requires cofactors like copper ions.
- Monolignols are held in place by temporary hydrogen bonds.
- Marks Allocation:
- Any five correct points covering laccase action and enzyme mechanics: 5 Marks
Question 5: Signal Transduction and Cell Cycle Regulation
5(a) Ligand Binding and Signal Transduction
- Process Overview:
- Ligand Secretion:
- Cells secrete ligands or transport them through the circulatory system.
- Receptor Binding:
- Ligands bind to specific, complementary receptors on target cells.
- Signal Transduction:
- Binding triggers intracellular reactions, such as the activation of secondary messengers (e.g., cyclic AMP).
- Initiates an enzyme cascade within the target cell.
- Ligand Secretion:
- Key Points:
- Specificity: Ligands must specifically bind to their receptors.
- Amplification: Secondary messengers amplify the signal inside the cell.
- Marks Allocation:
- Any two correct points describing ligand binding and signal transduction: 2 Marks
5(b) Non-Competitive Inhibition of Enzymes
- Mechanism:
- Binding Site:
- Non-competitive inhibitors bind to an allosteric site, not the active site.
- Conformational Change:
- Binding induces a change in the enzyme’s shape.
- Effect on Active Site:
- Active site becomes less complementary to the substrate, reducing enzyme activity.
- Binding Site:
- Key Points:
- Irreversible: Non-competitive inhibition cannot be overcome by increasing substrate concentration.
- Enzyme Functionality: Alters the enzyme’s ability to catalyze reactions without directly blocking substrate binding.
- Marks Allocation:
- Any two correct points explaining non-competitive inhibition: 2 Marks
5(c) Cell Cycle Inhibitors
5(c)(i) Palbociclib / p21Cip1
- Function:
- Inhibits cyclin-dependent kinases (CDKs) necessary for DNA replication.
- Stops DNA replication during the S phase, preventing cell division.
- Key Points:
- Role in Cancer Treatment: Halts uncontrolled cell proliferation by disrupting normal DNA replication.
- Marks Allocation:
- Correct explanation of inhibitor function: 2 Marks
5(c)(ii) RO-3306
- Function:
- Stops the cell cycle in the G₂ phase.
- Prevents mitosis, maintaining high numbers of mitochondria and ensuring DNA replication has occurred.
- Key Points:
- Cell Cycle Control: Inhibits progression into mitosis, thereby controlling cell proliferation.
- Research Applications: Used to study cell cycle dynamics.
- Marks Allocation:
- Correct explanation of inhibitor function: 2 Marks
5(d) Control of the Cell Cycle
- Mechanism:
- Stopping Before Mitosis/Cytokinesis:
- Prevents uncontrolled cell division, which can lead to tumor growth.
- Stopping Before Mitosis/Cytokinesis:
- Effect:
- Tumor Suppression: Reduces the risk of increasing tumor size by regulating cell division.
- Marks Allocation:
- Correct explanation of cell cycle control: 2 Marks
Question 6: Molecular Biology and Genetics
6(a) Differences Between mRNA and DNA
- Comparison Table:
Feature | mRNA | DNA |
---|---|---|
Strands | Single-stranded | Double-stranded (double helix) |
Sugar | Ribose | Deoxyribose |
Bases | Adenine, Cytosine, Guanine, Uracil | Adenine, Cytosine, Guanine, Thymine |
Structure | Shorter, fewer nucleotides | Longer, more nucleotides |
- Key Points:
- mRNA:
- Transcribed from DNA.
- Carries genetic information to ribosomes for protein synthesis.
- Contains uracil instead of thymine.
- DNA:
- Stores genetic information.
- Composed of two complementary strands forming a double helix.
- Contains thymine instead of uracil.
- mRNA:
- Marks Allocation:
- Any three correct differences: 3 Marks
6(b) Base Pairing and Hydrogen Bonds
6(b)(i) Incorrect Base Pairing: P and B
- Key Points:
- P and B Bases:
- Artificial or incorrect base pairs.
- In natural DNA, adenine pairs with thymine, and cytosine pairs with guanine.
- P and B Bases:
- Marks Allocation:
- Correct identification of incorrect base pairing: 1 Mark
6(b)(ii) Correct Base Pairing: C and G
- Key Points:
- Cytosine (C) and Guanine (G):
- Held together by three hydrogen bonds.
- Provides greater stability to the DNA double helix compared to adenine-thymine pairs.
- Cytosine (C) and Guanine (G):
- Marks Allocation:
- Correct explanation of C-G pairing and hydrogen bonds: 2 Marks
General Exam Tips
- Diagram Labeling:
- Ensure all diagrams are accurately labeled with key structures.
- Include annotations where necessary to clarify functions and interactions.
- Units and Conversions:
- Always include appropriate units in measurements.
- Be comfortable converting between units (e.g., mm to µm).
- Understanding Processes:
- Focus on understanding the mechanisms behind physiological and biochemical processes rather than just memorizing facts.
- Application of Knowledge:
- Be prepared to apply concepts to different scenarios, such as how mutations affect protein function or how transport mechanisms respond to environmental changes.
- Answer Structuring:
- Structure answers clearly, addressing each part of the question.
- Use scientific terminology accurately and concisely.
- Time Management:
- Allocate time based on the marks available for each question.
- Ensure you answer all parts of multi-part questions.
- Practice Past Papers:
- Familiarize yourself with the exam format and question styles.
- Time yourself while practicing to improve speed and accuracy.
Read each question and the statements below it. Click on the ONE statement you believe is INCORRECT. If you choose correctly, the reason why it’s wrong will appear, and you’ll earn a point.
You need to prepare 10 cm³ of an 80% protease solution starting from a 100% stock solution (P) and distilled water (W) using proportional dilution. Which step below describes an incorrect action or calculation for this specific task?
You are setting up an experiment to investigate how protease concentration affects the time it takes for 2 cm³ of milk to clot when 1 cm³ of protease solution is added. You will test concentrations of 100%, 80%, 60%, 40%, and 20%. Which step below describes an incorrect procedure for setting up the results table or recording the data?
When visually observing the test tubes to determine the precise moment the milk begins to clot, several factors can introduce errors. Which of the following is least likely to be a significant source of error specifically related to the visual judgement of the clotting endpoint?
Repeating experimental procedures multiple times (e.g., measuring the clotting time twice for each concentration) is a fundamental aspect of good scientific practice. Which statement below describes a reason that is incorrect or not a primary purpose of performing repeats?
You now want to estimate the protease concentration in an unknown fruit extract (U) using the same experimental setup where you added 1 cm³ of known protease solutions to 2 cm³ of milk. Which step below describes an incorrect action when testing the unknown extract U if you want to ensure a fair comparison?
Suppose the unknown fruit extract U took 95 seconds to clot the milk. Your previous results for known concentrations were: 100% (30s), 80% (45s), 60% (65s), 40% (85s), 20% (130s). How should you correctly interpret the result for U to estimate its protease concentration? Which step below describes an incorrect interpretation or action?
Having made a preliminary estimate that the protease concentration in U lies between 20% and 40%, you want to refine this estimate to be more accurate. Which of the following procedural modifications would be least effective or incorrect for achieving a more accurate estimate?
The activity of the protease actinidin was measured at various pH values, yielding the following data pairs (pH, Activity in µmol min⁻¹ mg⁻¹): (1.8, 0.00), (4.0, 20.25), (5.1, 24.00), (6.1, 28.25), (7.4, 22.50), (8.5, 6.75). Which statement below incorrectly describes the relationship shown in this data?
Considering the protease activity data showing an optimum around pH 6.1 and much lower activity at pH 1.8 and 8.5, which statement below provides an incorrect biochemical explanation for this phenomenon?
You are preparing a plan diagram (low power, showing tissue distribution) of a transverse section of a xerophytic leaf that features infoldings on the lower surface containing vascular bundles and trichomes. Which of the following describes an incorrect technique or feature for a standard plan diagram?
You need to create a detailed, high-power drawing showing three adjacent lower epidermal cells and one associated trichome (hair) from the xerophytic leaf slide. Which step below describes an incorrect procedure or convention for this type of biological drawing?
Observing the transverse section of the xerophytic leaf slide, you need to identify one structural adaptation to dry conditions other than the presence of trichomes. Which of the following features is not considered a typical xerophytic adaptation likely to be observed in such a leaf structure?
On a micrograph, you measure the total width of a pair of guard cells as 40 mm (line P-Q) and the width of the stomatal pore between them as 12 mm (line R-S). You need to calculate the pore width as a percentage of the total guard cell width, expressing the answer to two significant figures. Which step below shows an incorrect part of the calculation process or result?
You are comparing two micrographs. Micrograph 1 shows large, irregularly shaped (‘jigsaw puzzle’) epidermal cells and few, oval stomata, with visible nuclei. Micrograph 2 shows smaller, more regular epidermal cells and numerous, rounded stomata, nuclei not visible. Which statement makes an incorrect comparison based on these observations?